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A stone and a ball are thrown vertically upwards with different initial speeds 20m/s and 10m/s respectively. If the maximum height of the ball is h, what is the maximum height of the stone?

Respuesta :

jacob193

Answer:

4h if there's no air resistance.

Explanation:

Consider the equation that relates acceleration [tex]a[/tex], displacement [tex]x[/tex], initial velocity [tex]u[/tex], and final velocity [tex]v[/tex]:

[tex]\displaystyle x = \frac{v^{2} - u^{2}}{2a}[/tex].

For both the stone and the ball:

  • [tex]a = g = \rm -9.81\; m\cdot s^{-2}[/tex];
  • [tex]v = \rm 0\;m \cdot s^{-1}[/tex] when the objects are at their highest point: all kinetic energy are converted to potential energy;

[tex]x[/tex] is the height that needs to be found.

[tex]\displaystyle x = \frac{-u^{2}}{g}[/tex] for both objects.

[tex]u[/tex] of the stone is twice that of the ball. As a result, [tex]u^{2}[/tex] of the stone will be four times that of the ball. As a result, the maximum height of the stone will be four times that of the ball.

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