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How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
of H,0 is 4.1841/gC)

Respuesta :

jaimyrenji

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

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