Answer:
12000m
Explanation:
[tex]d = vt[/tex]
d = distance; v = average speed; t = time.
time should be in seconds. Using 1h = 3600s
[tex]t = 1.5h = 1.5*(3600s)=5400s[/tex]
Using this time:
[tex]d=(2.22m/s)(5400s)=11988m[/tex]
Remember to round using significant figures (just 2). distance = 12000m
The total distance jogger runs in 1.5 hours with an average speed of 2.22 m/s is 11988 m.
To find the distance traveled by a person or thing when average speed and time is given firstly we need to check whether units of all given values be either in SI system or MKS system. If in the given values one value is in MKS and another value is in SI system we need to convert the values in either of the system.
The average speed is given by the formula:
[tex]\text {Average speed}=\frac{\text {Total distance traveled}}{\text {Total time taken}}[/tex]
Given that, average speed is 2.22 m/s and time taken is 1.5 hours.
Convert time given into seconds so that all values be in MKS system.
[tex]1.5 \times 60 \times 60=5400 \text { seconds }[/tex]
Now,
[tex]\Rightarrow \text { Average speed }=2.22=\frac{\text { Total distance travelled }}{5400}[/tex]
[tex]\Rightarrow \text { Total distance traveled }=2.22 \times 5400[/tex]
[tex]\therefore \text { Total distance traveled}=11988 \ \mathrm{m}[/tex]
Hence, we can say that jogger 11988 m.
