Answer:
The value of f(1) is greater than value of f(3)
Step-by-step explanation:
We substitute..x = 1..into the given equation....where we say...
; -2(1)^2 + 3(1) + 10 = 11
Then we substitute..x = 3..into the given equation
;-2(3)^2 + 3(3) + 10
;-2(9) + 9 + 10 = 1
If f(1) = 11 and f(3) = 1...then the value of f(1) is greater than the value of f(3)
Answer:
C. The value of f(1) is larger than the value of f(3).
Step-by-step explanation:
We have been given a function [tex]f(x)=-2x^2+3x+10[/tex]. We are asked to find [tex]f(1)[/tex] and [tex]f(3)[/tex].
To find [tex]f(1)[/tex], we will substitute [tex]x=1[/tex] in our given function.
[tex]f(x)=-2x^2+3x+10[/tex]
[tex]f(1)=-2(1)^2+3(1)+10[/tex]
[tex]f(1)=-2*1+3+10[/tex]
[tex]f(1)=-2+13[/tex]
[tex]f(1)=11[/tex]
To find [tex]f(3)[/tex], we will substitute [tex]x=3[/tex] in our given function.
[tex]f(x)=-2x^2+3x+10[/tex]
[tex]f(3)=-2(3)^2+3(3)+10[/tex]
[tex]f(3)=-2*9+9+10[/tex]
[tex]f(3)=-18+19[/tex]
[tex]f(3)=1[/tex]
We can see that [tex]f(1)=11[/tex] and [tex]f(3)=1[/tex]. Therefore, option C is the correct choice.
