Answer:
[tex]\bold{Q13}\ \angle W\\\\\bold{Q14}\ \angle S\\\\\bold{Q15}\ side\ WA\\\\\bold{Q16}\ \triangle PTA[/tex]
Step-by-step explanation:
For Q13, Q14, Q15
[tex]\text{for}\ \overline{WA}\ \text{and}\ \overline{AS}\ -\ A\ \text{is common}.\ \text{Therefore inclu}\text{ded angle is}\ \angle A\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{WA}\to\angle W\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{SA}\to\angle S\\\\============================[/tex]
[tex]\text{Inc}\text{lude side between}\ \angle A\ \text{and}\ \angle W\ \text{is}\ AW\ (WA).\\\\\text{Inc}\text{lude side between}\ \angle S\ \text{and}\ \angle W\ \text{is}\ SW\ (WS).\\\\\text{Inc}\text{lude side between}\ \angle A\ \text{and}\ \angle S\ \text{is}\ AS\ (SA).[/tex]
Q16
[tex]O\ \leftrightarrow\ T\\B\ \leftrightarrow\ A\\R\ \leftrightarrow\ P\\\\\text{Therefore}\ \triangle ROB\ \cong\ \triangle PTA[/tex]
