[tex]\bf \cfrac{2}{7}(x-2)=4x\implies \cfrac{2(x-2)}{7}=4x\implies 2(x-2)=28x\implies 2x-4=28x \\\\\\ -4=26x\implies \cfrac{-4}{26}=x\implies -\cfrac{2}{13}=x[/tex]
Answer:
SECOND OPTION: [tex]x=-\frac{2}{13}[/tex]
Step-by-step explanation:
Given the following equation:
[tex]\frac{2}{7}(x-2)=4x[/tex]
We need to to solve for "x" in order to find its value.
First, we need to apply Distributive property:
[tex]\frac{2x-4}{7}=4x[/tex]
Now, we multiply both sides of the equation by 7:
[tex](7)(\frac{2x-4}{7})=(4x)(7)\\\\2x-4=28x[/tex]
Then, we can subtract [tex]2x[/tex] from both sides of the equation:
[tex]2x-4-2x=28x-2x\\\\-4=26x[/tex]
And finally we can divide both sides by 26:
[tex]\frac{-4}{26}=\frac{26x}{26}\\\\x=-\frac{2}{13}[/tex]
