Answer:
[tex]\boxed{\text{d. 210 g Fe}}[/tex]
Explanation:
We will need a balanced equation with moles and molar masses, so let’s gather all the information in one place.
M_r: 55.845
3Fe + 4H₂O → Fe₃O₄ + 4H₂
n/mol: 5
1. Calculate the moles of Fe
[tex]\text{Moles of Fe} = \text{5 mol H}}_{2}\text{O}} \times \dfrac{\text{3 mol Fe}}{\text{4 mol H$_{2}$O}} = \text{3.75 mol Fe}[/tex]
2. Calculate the mass of Fe
[tex]\text{Mass of Fe} =\text{3.75 mol Fe}\times \dfrac{\text{55.845 Fe}}{\text{1 mol Fe}}=\textbf{210 g Fe}\\\text{You will need }\boxed{\textbf{210 g Fe}}[/tex]
