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Two balls, A and B are thrown at the same angle above horizontal, but initial velocity of ball A is two times greater than initial velocity of ball B. Ignore air resistance. We can conclude that maximum height reached by ball A is (section 4.3) two times maximum height reached by B greater than maximum height reached by B, but we don't have enough information to give exact answer. four times the maximum height reached by B same as maximum height reached by B

Respuesta :

Answer:

Explanation:

Let the initial velocity of A and B be  2U₁ and U₁ at a common angle of θ.

At maximum height H  , Velocity v =0

For vertical  displacement

Vertical component = U₁ Sinθ and

v² = u² - 2gH

H = u² / 2g

H₁ = (2U₁ sinθ)² /  2g

H₂ = (U₁ sinθ)² / 2g

H₁ /H₂ = 4/1

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