Respuesta :
Explanation:
Molecular mass of sugar = [tex]C_{12}H_{22}O_{11}[/tex] : = 432 g/mol
Atomic mass of carbon atom = 12 g/mol
Atomic mass of hydrogen atom = 1 g/mol
Atomic mass of oxygen atom = 16 g/mol
a) Percentage of an element in a compound:
[tex]\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100[/tex]
Percentage of carbon by weight in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{12\times 12 g/mol}{342 g/mol}\times 100=42.10\%[/tex]
Percentage of hydrogen by weight in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{22\times 1g/mol}{342 g/mol}\times 100=6.43\%[/tex]
Percentage of oxygen by weight in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{11\times 16g/mol}{342 g/mol}\times 100=51.46\%[/tex]
b) Percentage of mole each of the elements present in sugar:
=[tex]\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}\times 100[/tex]
In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.
Percentage of carbon by mole in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{12 mol}{45 mol}\times 100=26.66\%[/tex]
Percentage of hydrogen by mole in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{22 mol}{45 mol}\times 100=48.88\%[/tex]
Percentage of oxygen by mole in [tex]C_{12}H_{22}O_{11}[/tex]:
[tex]\frac{11 mol}{45 mol}\times 100=24.44\%[/tex]
