Respuesta :

Answer:

ky=3-2x

y=(3-2x)/k

y=(7-kx)/8

(3-2x)/k=(7-kx)/8

8(3-2x)=(7-kx)k

24-16x=7k-k*kx

24=7k-kkx+16x

24+7k=kkx+16x

24+7k=x(k^2+16)

The lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

Two linear equations in two variables are:

2x + ky = 3 and

kx + 8y = 7

As we know the condition for the lines to intersect or have unique solutions:

2/k ≠ k/8

After cross multiplication:

k² ≠ 16

k ≠ ±4

The values of k can be anything except 4 and - 4

Thus, the lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.

Learn more about the linear equation here:

brainly.com/question/11897796

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