Answer:
The stoichiometric factor relating KMnO4 and MnCl is 1:1
Explanation:
The complete equation is
[tex]16HCl + 2KMnO_{4} → 5Cl_{2} + 2MnCl_{2} + 2KCl + 8H_{2} O[/tex]
Any chemical equiation can be read in terms of moles. In this equiation, 6 moles of hydrochloric acid react with 2 moles of potassium permanganate to produce 2 moles of manganese(II) chloride.
As can be seen, two moles of the permanganate produce two moles of the chloride, then the stoichiometric factor is 1 to 1.