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A reaction has a rate constant of 0.00774 sec-1, how much of the compound (in mol/L) is left after 8.93 sec, if there was 0.652 mol/L at the start? (give answer to 3 decimal places)?

how do you know the order of the reaction???

Respuesta :

Answer:

0.608 mol/L compound is left after 8.93 sec

Explanation:

This is a first order reaction because unit of rate constant is [tex](time)^{-1}[/tex] (or [tex]sec^{-1}[/tex])

For a first order reaction, integrated rate law is-

                  [tex]ln\frac{C_{0}}{C_{t}}=k.t[/tex]

where [tex]C_{0}[/tex] is initial concentration of reactant, [tex]C_{t}[/tex] is concentration of reactant after t time and k is rate constant

Here [tex]C_{0}[/tex] = 0.652 mol/L, k = 0.00774 [tex]sec^{-1}[/tex]) and t = 8.93 sec

So, [tex]ln(\frac{0.652mol/L}{C_{t}})=0.00774 sec^{-1}\times 8.93 sec[/tex]

So, [tex]C_{t}=0.608mol/L[/tex]

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