Respuesta :
Answer:
Electric field on proton
[tex]E=3.12\times 10^9\ N/C[/tex]
Explanation:
Given that
[tex]Force,F=5\times 10^{-10}\ N[/tex]
We know that
Charge on proton
[tex]q=1.6\times 10^{-19}\ C[/tex]
We know that
Force = Electric field x Charge
F= E x q
[tex]E=\dfrac{F}{q}\ N/C[/tex]
[tex]E=\dfrac{5\times 10^{-10}}{1.6\times 10^{-19}}\ N/C[/tex]
[tex]E=3.12\times 10^9\ N/C[/tex]
Electric field on proton
[tex]E=3.12\times 10^9\ N/C[/tex]
The electric field on the proton is [tex]3.125 \times 10^9 \;\rm N/C[/tex].
How do you calculate the electric field?
Given that the force on the proton is 5 X 10^-10 N. We know that the charge on the proton is 1.6 X 10^-19 C.
The force can be written as given below.
[tex]F = Eq[/tex]
Where F is the force, E is the electric field and q is the charge on the proton. Substituting the values, we get the electric field.
[tex]5 \times 10^{-10} = E \times 1.6\times 10^{-19}[/tex]
[tex]E = 3.125 \times 10^9 \;\rm N/C[/tex]
Hence we can conclude that the electric field on the proton is [tex]3.125 \times 10^9 \;\rm N/C[/tex].
To know more about force and electric field, follow the link given below.
https://brainly.com/question/2598777.
