Answer:
The father start with $16
Step-by-step explanation:
Let
x -----> the original amount of money
step 1
Your father gives one-half of the money in his pocket to your mother
[tex]\frac{1}{2}(x)=\frac{1}{2}x[/tex]
The remaining is
[tex]x-\frac{1}{2}x=\frac{1}{2}x[/tex]
step 2
Your father gives, one-fourth of what is left to your brother
[tex](\frac{1}{4})\frac{1}{2}x=\frac{1}{8}x[/tex]
The remaining is
[tex]\frac{1}{2}x-\frac{1}{8}x=\frac{3}{8}x[/tex]
step 3
Your father gives one-third of what then remains to your sister
[tex](\frac{1}{3})\frac{3}{8}x=\frac{3}{24}x[/tex]
The remaining is
[tex]\frac{3}{8}x-\frac{3}{24}x=\frac{6}{24}x=\frac{1}{4}x[/tex]
step 4
Your father gives the rest with you
[tex]\frac{1}{4}x=\$4[/tex]
[tex]x=\$16[/tex]
therefore
The father start with $16
