Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly
for lunch. If the lily pads are spaced 2.4 m apart, and Ferdinand jumps with a
speed of 5.0 m/s, taking 0.60 s to go from lily pad to lily pad, at what angle
must Ferdinand make each of his jumps?​

Respuesta :

Answer: [tex]36.86\°[/tex]

Explanation:

According to the described situation we have the following data:

Horizontal distance between lily pads: [tex]d=2.4 m[/tex]

Ferdinand's initial velocity: [tex]V_{o}=5 m/s[/tex]

Time it takes a jump: [tex]t=0.6 s[/tex]

We need to find the angle [tex]\theta[/tex] at which Ferdinand jumps.

In order to do this, we first have to find the horizontal component (or x-component) of this initial velocity. Since we are dealing with parabolic movement, where velocity has x-component and y-component, and in this case we will choose the x-component to find the angle:

[tex]V_{x}=\frac{d}{t}[/tex] (1)

[tex]V_{x}=\frac{2.4 m}{0.6 s}[/tex] (2)

[tex]V_{x}=4 m/s[/tex] (3)

On the other hand, the x-component of the velocity is expressed as:

[tex]V_{x}=V_{o}cos\theta[/tex] (4)

Substituting (3) in (4):

[tex]4 m/s=5 m/s cos\theta[/tex] (5)

Clearing [tex]\theta[/tex]:

[tex]\theta=cos^{-1} (\frac{4 m/s}{5 m/s})[/tex]

[tex]\theta=36.86\°[/tex] This is the angle at which Ferdinand the frog jumps between lily pads