Answer:
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
Solution:
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) [tex]\times[/tex] p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = [tex]\frac{\text { number of good coils }}{\text { total number of coils }}[/tex]
Hence, p(getting 2 good coil for two selection) = [tex]\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}[/tex]
