Answer:
18, 108
Step-by-step explanation:
Given
[tex]a_{n}[/tex] = 6[tex]a_{n-1}[/tex] with a₁ = 3
This is a recursive formula which allows the term in the sequence to be found from the previous term.
To find a₂ and a₃ substitute n = 2, n = 3 into the formula
a₂ = 6 × a₁ = 6 × 3 = 18
a₃ = 6 × a₂ = 6 × 18 = 108
