Answer:
1.44 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a[/tex]
This velocity will be the initial velocity of the car when it passes through the first building
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 3=5a\times 0.4+\frac{1}{2}\times a\times 0.4^2\\\Rightarrow a=1.44\ m/s^2[/tex]
The acceleration of the car is 1.44 m/s²