Answer with Step-by-step explanation:
Since the given event is binary we can use Bernoulli's probability to sove the problem
Thus for an event 'E' with probability of success 'p' the probability that the event occurs 'r' times in 'n' trails is given by
[tex]P(E)=\frac{n!}{(n-r)!\cdot r!}\cdot p^{r}\cdot (1-p)^{n-r}[/tex]
Part a)
For part a n = 11 , r =9, p = 0.75
Applying values we get
[tex]P(E)=\frac{11!}{(11-9)!\cdot 9!}\cdot (0.75)^{9}\cdot (1-0.75)^{11-9}\\\\\therefore P(E)=0.2581[/tex]
Part b)
For part b n = 20 , r = 16 , p=0.75
Applying values we get
[tex]P(E)=\frac{20!}{(20-16)!\cdot 16!}\cdot (0.75)^{16}\cdot (1-0.75)^{20-16}\\\\\therefore P(E)=0.1896[/tex]