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You have screened for several new recessive mutations in a species of wasp. Wasps homozygous for apricot (aa) have pale orange eyes. (Wild-type eyes are brown.) Wasps homozygous for blunt (bb) have short wings. (Wild-type wings are long.) You make a pure-breeding double-mutant (apricot, blunt) line and cross it with wild-type wasps. The F1 is wild-type in appearance.

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Answer:

The F1 will have mostly dominant phenotype, nevertheless, some recesive phenotype appears as aa - ab and bb

Explanation:

If you make a pure-breeding double-mutant (apricot, blunt) line - you will have heterozygous ab

and if you cross it with wild-type wasps - you will have for apricot: AA - Aa and for blunt BB - Bb (as A and B are dominant gen)

Then, you could have for F1 breed:

*- ab / AA: Aa - BA

*- ab / Aa: aA - aa - bA - ba

*- ab / BB: Ba - aB

*- ab / Bb: aB - ab - bB - bb

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