Answer:
See explanation
Step-by-step explanation:
1. The 1st Beatles song heard is the 5th song played means that first 4 songs are not Beatles songs (there are 100 - 10 = 90 such songs) and the 5th song is Beatles song (there are 10 such songs). Hence, the probability that the first Beatles song heard is the fifth song played is
[tex]\dfrac{C^{90}_4\cdot C^{10}_1}{C^{100}_5}=\dfrac{2,555,190\cdot 10}{75,287,520}\approx 0.3394[/tex]
2. There are exactly two Beatles songs in the first five songs played means there are 2 Beatles songs and 3 not Betles songs (the number when these songs are played do not matter). Hence, the probability that there are exactly two Beatles songs in the first five songs played is
[tex]\dfrac{C^{10}_2\cdot C^{90}_3}{C^{100}_5}=\dfrac{45\cdot 117,480}{75,287,520}\approx 0.0702[/tex]