Answer:
object A will travel four times as far as object B.
Explanation:
The equation that describes the distance as a function of aceleration, initial speed and time is:
[tex]x=v_{0}t+\frac{1}{2} at^2[/tex]
So,
[tex]v_{0]=0[/tex]in both objects, because says accelerate from rest.
[tex]t[/tex] is the same for both objects.
The only diference is the time of acceleration, lets say [tex]t_A[/tex] be the time for object A, and [tex]t_B[/tex] be the time for object B.
Equation for object A
[tex]x=\frac{1}{2} a{t_A]^2[/tex]
Equation for object B
[tex]x=\frac{1}{2} a{t_B}^2[/tex]
If [tex]t_A=2*t_B[/tex], then equation for object A is
[tex]x=\frac{1}{2} a{t_A}^2=\frac{1}{2} a{(2*t_B)}^2=\frac{1}{2} a4{t_B}^2= 2 a{t_B}^2[/tex]
So comparing both equations, object A will travel four times as far as object B.