Answer:
7.5%
Explanation:
The genes vg+/vg and pr+/pr are linked.
A pure-breeding red-eyed fly with vestigial wings was crossed with a pure-breeding purple-eyed fly with normal wings.
This cross can be written down as:
[tex]\frac{pr+ \ vg }{pr+ \ vg}[/tex] x [tex]\frac{pr \ vg+ }{pr \ vg+}[/tex]
The wild-type F1 would be:
[tex]\frac{pr+ \ vg}{pr \ vg+}[/tex]
They are test crossed with a homozygous recessive individual that can produce only one type of gamete: pr vg
The F1 flies will produce 4 types of gametes:
Each time recombination happens, the two possible recombinant gametes are generated. Because the recombination frequency between the two genes is 15% altogether, each recombinant gamete will appear with half that frequency, 7.5% of the times.
The pr+ vg+ recombinant gamete will be produced with a frequency of 7.5%, and when it's combined with the pr vg gamete from the test cross individual, it will give rise to offpring with WT phenotype.
The expected percentage of the progeny to have the WT phenotype is 5 %
Progeny means the next generation, it means the offspring or children.
Parental
[tex]\rm \dfrac{Pr^+Vg}{Pr^+Vg} \times \dfrac{PrVg^+}{PrVg^+}[/tex]
F1 generation
[tex]\rm \dfrac{Pr^+Vg}{Pr^+Vg} \times \dfrac{PrVg^+}{PrVg^+}[/tex]
Cross over
Red eye vestigial wings
[tex]\rm \dfrac{ Pr^+Vg}{PrVg}[/tex]
Purple eye Normal wings
[tex]\rm \dfrac{ PrVg}{PrVg}[/tex]
Recombination at the F1 genotype from the parent to
[tex]\dfrac{Pr^+Vg^+}{PrVg} = 10\%[/tex]
Test Cross for the recombination:
[tex]\rm \dfrac{Pr^+Vg}{PrVg} \times \dfrac{PrVg}{PrVg}[/tex]
F1
Red eye vestigial wings
[tex]\rm \dfrac{ Pr^+Vg}{PrVg}[/tex]
Purple eye Normal wings
[tex]\rm \dfrac{ PrVg}{PrVg}[/tex]
Thus, the percentage will be 5%
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