Answer:
Let the growth function that shows the population in millions after x years,
[tex]P=P_0(1+r)^x[/tex]
Where,
[tex]P_0[/tex] = initial population,
r = growth rate per year,
Suppose the population is estimated since 1950,
Thus, if x = 0, P = 2560,
[tex]\implies 2560 = P_0 (1+r)^0\implies P_0 = 2560[/tex]
Now, if x = 10 ( that is, on 1960 ), P = 3040,
[tex]3040=2560(1+r)^{10}\implies r = 0.017[/tex]
Hence, the required function that shows the population after x years,
[tex]P=2560(1.017)^x[/tex]
If x = 42,
The population in 1992 would be,
[tex]P=2560(1.017)^{42}\approx 5196.608365\text{ millions}[/tex]
if x = 80,
The population in 2030 would be,
[tex]P=2560(1.017)^{80}\approx 9860.891929\text{ millions}[/tex]