Answer:
[tex]y=-5x+16[/tex]
Step-by-step explanation:
we know that
The equation of a line in point slope form is equal to
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]point\ (2,6)\\m=-5[/tex]
substitute the values
[tex]y-6=-5(x-2)[/tex] ----> equation in point slope form
Convert to slope intercept form
[tex]y=mx+b[/tex]
Distribute the right side
[tex]y-6=-5x+10[/tex]
Adds 6 both sides
[tex]y=-5x+10+6[/tex]
[tex]y=-5x+16[/tex]