Answer:
the potential energy increases and the electric potential increases
Explanation:
we know here that Voltage i.e. (Electric potential) increases from the initial point to the final point
consider if 2 object of different charge 1 is twice the charge of other moveing in same distance in electric filed
than object of twice the charge require twice the force so twice amount of work
This work change the potential energy by equal amount of work done
so electric potential energy is depend on the amount of charge on object
so if work being done on a positive test charge by an external force in moving the charge from one location to another
the potential energy increases and the electric potential increases
When a positive test charge is moved from one location to another, the potential energy increases and the electric potential energy increases.
The work done in moving a unit positive test charge from infinity to a certain point in the electric field is known as potential energy.
V = E x d
V = (F/q) x d
where;
Thus, when a positive test charge is moved from one location to another, the potential energy increases and the electric potential energy increases.
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