Answer:
0.55
Step-by-step explanation:
Let 100 be the number of all car owners.
- 12% of the drivers own model A car, then 12 drivers own car A;
- 30% own model B, then 30 drivers own car B;
- 26% own model C, then 26 drivers own car C;
- 3% own all three models, then 3 drivers own all 3 cars;
- 5% own models A and B, then 5 drivers own cars A and B;
- 12% own models B and C, then 12 own cars B and C;
- 9% own models C and A, then 9 drivers own cars A and C.
Now,
- 3 drivers own all three cars;
- 5 - 3 = 2 drivers own only cars A and B;
- 12 - 3 = 9 drivers own only cars B and C;
- 9 - 3 = 6 drivers own only cars A and C;
- 12 - 3 - 2 - 6 = 1 driver owns only car A;
- 30 - 3 - 2 - 9 = 16 drivers own only car B;
- 26 - 3 - 9 - 6 = 8 drivers own only car C.
In total, there are
3 + 2 + 9 + 6 + 1 + 16 + 8 = 45 dirvers own cars A, B or C.
Thus, [tex]\dfrac{45}{100}[/tex] of drivers own cars A, B or C and [tex]\dfrac{55}{100}=0.55[/tex] do not own cars A, B, C.
