Answer:
(a) The x-component of velocity is 31.55 km/h
(b) The y-component of velocity is 44.92 km/hr
Solution:
As per the solution:
The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.
Velocity of ship A, [tex]\vec{u_{A}}[/tex] = 22 km/h towards South = [tex]- 22\hat{j}[/tex]
Velocity of ship B, [tex]\vec{u_{B}}[/tex] = 39 km/h Towards North east at an angle of [tex]36^{\circ}[/tex] = [tex]\vec{u_{B}} = 39sin36^{\circ} \hat{j}[/tex]
Now, the velocity of ship A relative to ship B:
[tex]\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}[/tex]
[tex]\vec{u_{A}} = - 22\hat{j}[/tex]
[tex]\vec{u_{B}} = 39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}[/tex]
Now,
[tex]\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}[/tex]
[tex]\vec{u_{AB}} = 31.55\hat{i} - 44.92\hat{j}[/tex]
