Answer:
35.71 N
Explanation:
The elevator starts from the rest means its initial velocity is zero.
Given that, the height achieved by the elevator in 1.4 s will be, [tex]S=1m[/tex]
Given that the mass of the bundle which is hold by passenger is, [tex]m=3.3 kg[/tex]
Now according to second equation of motion.
[tex]S=ut+\frac{1}{2}at^{2}[/tex]
Here, S is the height, u is the initial velocity, t is the time taken, and a is the acceleration.
Now initial velocity is zero therefore,
[tex]S=\frac{1}{2}at^{2}\\a=\frac{2S}{t^{2} }[/tex]
According to the free body diagram tension and acceleration in upward direction and weight is in downward direction.
So,
[tex]ma=T-mg\\T=m(g+a)[/tex]
Put the value of a from the above
[tex]T=m(g+\frac{2S}{t^{2} })[/tex]
Put all the variables.
[tex]T=3.3(9.8+\frac{2\times 1}{1.4^{2} })\\T=3.3(9.8+1.02)\\t=35.71N[/tex]
This the required tension.
