Answer:
The concentration of the standard NaOH solution is 0.094 moles/L.
Explanation:
In the titration, the equivalence point is defined as the point where the moles of NaOH (the titrant) and KHP (the analyte) are equal:
moles of NaOH = moles of KHP
[tex][NaOH]xV_{NaOH} = moles of KHP[/tex]
[tex][NaOH] = \frac{moles of KHP}{V_{NaOH}}[/tex]
The [tex]V_{NaOH}[/tex] is 40.82mL = 0.04082L and the moles of KHP are
[tex]0.7816g / 204.2212\frac{g}{mol} = 3.827x10^{-3} moles[/tex]
Replacing at the first equation:
[tex][NaOH] = \frac{3.827x10^{-3}moles}{0.04082L} = 0.094 moles/L[/tex]
