In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-19 C. If a single droplet was found to have a total charge of -9.60×10-19 C then how many excess electrons are contained within the drop?

Respuesta :

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, [tex]q=-9.6\times 10^{-19}\ C[/tex]

The measured charge of any single droplet, [tex]e=-1.6\times 10^{-19}\ C[/tex]

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

[tex]q=ne[/tex]

[tex]n=\dfrac{q}{e}[/tex]

[tex]n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}[/tex]

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.