Answer:
2.76m/s
Explanation:
The position x for a given time t and constant acceleration a is:
(1) [tex]x=\frac{1}{2}at^2[/tex]
The velocity v:
(2) [tex]v=at[/tex]
Solving equation 2 for time t:
(3) [tex]t=\frac{v}{a}[/tex]
Combining equations 1 and 3:
(4) [tex]x=\frac{v^2}{2a}[/tex]
Solving equation 4 for velocity v:
(5) [tex]v=\sqrt{2ax}[/tex]
For a = 0.465m/s² and x = 8.2m:
v = 2.76m/s
