Respuesta :
Answer:
11 m/s²
Explanation:
u = Initial velocity of the jet = 300 m/s
v = Final velocity of the jet = 400 m/s
s = Displacement of the jet = 3.1 km = 3100 m
a = Acceleration of the jet
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{400^2-300^2}{2\times 3100}\\\Rightarrow s=11.29=11\ m/s^2[/tex]
Acceleration of the jet is 11 m/s²
The acceleration of the jet is 11.29 m/s2.
How do you calculate the acceleration?
Given that the initial velocity of the jet is 300 m/s, the final velocity of the jet is 400 m/s. The distance traveled by jet is 3.1 km.
The acceleration of the jet is calculated as given below.
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance traveled by jet.
[tex]400^2 = 300^2 + 2\times a\times 3.1 \times 1000[/tex]
[tex]a = 11.29 \;\rm m/s^2[/tex]
Hence we can conclude that the acceleration of the jet is 11.29 m/s2.
To know more about velocity and acceleration, follow the link given below.
https://brainly.com/question/2239252.
