Answer:
The coordinates are A(-1,2)
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
In this problem we have
[tex]M(2,6)\\A(x_1,y_1)[/tex]
[tex]B(x_2,y_2) ---> B(5,10)[/tex]
substitute the given values
[tex](2,6)=(\frac{x_1+5}{2},\frac{y_1+10}{2})[/tex]
Solve for [tex]x_1[/tex]
[tex]2=(x_1+5)/2\\4=x_1+5\\x_1=4-5=-1[/tex]
Solve for [tex]y_1[/tex]
[tex]6=(y_1+10)/2\\12=y_1+10\\y_1=12-10=2[/tex]
therefore
The coordinates are A(-1,2)
