Answer:
[tex]y = 5cos(\frac{\pi }{12}(t-6.75))+7[/tex]
Step-by-step explanation:
You have been asked to find the values in the function:
[tex]y=Acos(B(t+C))+D[/tex]
First, calculate A, called the amplitude, as half the value from peak to peak (from lowtide to high tide):
[tex]A = (12-2)/2=5[/tex]
Then, calculate the vertical shift D as the average value between the high tide and lowtide:
[tex]D = (12+2)/2=7[/tex]
Then, if P is the natural period of the tide, you can calculate B, or the frequency as:
[tex]B=\frac{\pi }{P}=\frac{\pi }{12}[/tex]
Finally you need to find C or the phase shift thinking that for negative values, the function is shifted (displaced) to the right.
C=-6.75