Answer: a) There are 42% chances that both units will meet their objectives.
b) There are 88% chances that one or the other but not both of the units will be successful.
Step-by-step explanation:
Since we have given that
Probability that the Red unit will successfully meet its objectives = 60% = P(R)
Probability that Blue unit will successfully meet its objectives = 70% = P(B)
Probability that only Red unit will be successful = P(only Red) = 18%
As we know that
[tex]P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%[/tex]
Hence, there are 42% chances that both units will meet their objectives.
the probability that one or the other but not both of the units will be successful is given by
[tex]P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%[/tex]
Hence, there are 88% chances that one or the other but not both of the units will be successful.
