Respuesta :
Answer:
The magnitude of the displacement is 24.04 meters
Explanation:
Lets explain how to solve the problem
A man walks 17 meters east
Then 17 meters south
We need to find the magnitude of his displacement
Magnitude of displacement is a scalar quantity represents the distance,
as measured directly between the start point and the end point
Assume that the origin point is his starting point
East direction represented by positive part of x-axis
South direction is the negative part of the y-axis
The man walks 17 meters east, then his position at (17 , 0)
Then he walks 17 meters to south , his position is (17 , -17)
His starting position is at (0 , 0)
His final position is at (17 , -17)
The magnitude of displacement = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]
The magnitude of displacement = [tex]\sqrt{(17-0)^{2}+(-17-0)^{2}}[/tex]
The magnitude of displacement = [tex]\sqrt{(17)^{2}+(-17)^{2}}[/tex]
The magnitude of displacement = [tex]\sqrt{289+289}[/tex]
The magnitude of displacement = [tex]\sqrt{578}=24.04[/tex] meters
The magnitude of the displacement is 24.04 meters
Answer:
The magnitude of the displacement is 24.04 meters
Explanation:
Lets explain how to solve the problem
A man walks 17 meters east
Then 17 meters south
We need to find the magnitude of his displacement
Magnitude of displacement is a scalar quantity represents the distance,
as measured directly between the start point and the end point
Assume that the origin point is his starting point
East direction represented by positive part of x-axis
South direction is the negative part of the y-axis
The man walks 17 meters east, then his position at (17 , 0)
Then he walks 17 meters to south , his position is (17 , -17)
His starting position is at (0 , 0)
His final position is at (17 , -17)
The magnitude of displacement =
The magnitude of displacement =
The magnitude of displacement =
The magnitude of displacement =
The magnitude of displacement = meters
The magnitude of the displacement is 24.04 meters
