Answer:
Time, t = 5 seconds
Explanation:
It is given that,
Initial speed of the bike, u = 8 m/s
Final speed of the bike, v = 14 m/s
Length of the hill, d = 55 m
Firstly, we can find the acceleration of the bike. Let it is equal to a. It can be calculated using third equation of motion as :
[tex]a=\dfrac{v^2-u^2}{2d}[/tex]
[tex]a=\dfrac{(14)^2-(8)^2}{2\times 55}[/tex]
[tex]a=1.2\ m/s^2[/tex]
Let t is the time passes during the descent. It can be calculated using the first equation of motion as :
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{14-8}{1.2}[/tex]
t = 5 seconds
So, the time passes during the descent is 5 seconds. Hence, this is the required solution.
