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a ball is rolled down hill with an initial velocity of 4.2 m/s. how far will it roll in 11.6s if it accelerates at 2.3m/s2​

Respuesta :

MathPhys

Explanation:

Given:

x₀ = 0 m

v₀ = 4.2 m/s

t = 11.6 s

a = 2.3 m/s²

Find: x

x = x₀ + v₀ t + ½ at²

x = 0 m + (4.2 m/s) (11.6 s) + ½ (2.3 m/s²) (11.6 s)²

x ≈ 203 m

Round as needed.

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