notanotherusername
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How do you get 40y from the difference of 2 squares with the problem (5y+4+3x)(5y+4-3x)? I understand distribution method. I don't know where the 40y comes from using the special product method.

Respuesta :

ghanami

Answer:

Step-by-step explanation:

(5y+4+3x)(5y+4-3x) = (5y+4)² - (3x)²......(from the difference of 2 squares )

by identity : (a+b)(a-b) = a² - b²

in this exercice ; a = 5y+4 and b  = 3x

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