Answer:
[tex]2\pi \approx 6.28\ meters[/tex]
Step-by-step explanation:
Mei's horse is 3 meters from the center of the carousel. After one rotation, Mei travelled
[tex]l_M=2\pi r=2\pi \cdot 3=6\pi\ meters[/tex]
Anju's horse is 2 meters from the center. After one rotation, Mei travelled
[tex]l_A=2\pi r=2\pi \cdot 2=4\pi\ meters[/tex]
The difference in their travelled distances is
[tex]l_M-l_A=6\pi -4\pi =2\pi \approx 6.28\ meters[/tex]
To solve the problem we must know about the concept of Circumference.
The Mie's horse has traveled 3.3 m more than Anju's horse.
The circumference is the boundary of the circle or can say circumference is the perimeter of a circle. It is calculated by the formula,
Circumference = 2 π r
where r is the radius of the circle.
Given to us
Mei's horse is 3 meters from the center of the carousel.
Anju's horse is 2 meters from the center.
As we know the Carousel, has rotary motion, therefore, both the horses will follow the circumference of the circle with the radius being the distance of the horses from the center.
Distance traveled by Mei's horse
= 2 x π x Distance of Mei's horse from the center of the carousel
= 2 x π x 3
= 18.8495 m
Distance traveled by Anju's horse
= 2 x π x Distance of Anju's horse from the center of the carousel
= 2 x π x 2
= 12.5664 m
Difference between the distance traveled by Mei's horse and Anju's horse
= Distance traveled by Mei's horse - Distance traveled by Anju's horse
= 18.8495 m - 12.5664 m
= 3.2831 m ≈ 3.3 m
Hence, the Mie's horse has traveled 3.3 m more than Anju's horse.
Learn more about Circumference:
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