Respuesta :
Answer:
A. The rate of heat transfer through the material would increase.
Explanation:
To calculate the heat transfer in a heat exchanger you decide that there is not heat leakage to the surroundings, that means that magnitude of the two transfer rates will be equal. Any heat lost by the hot fluid, is gained by the cold fluid. The equation that describes this is Q = m×Cp×dT
Where:
heat = mass flow ×specific heat capacity × temperature difference
So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.
Answer:
A. The rate of heat transfer through the material would increase.
Explanation:
Remember that when doing heat transfer problems you will always have a hotter side than the other, and that is the one that you´d like to cool off, ig you increase the rate of flow of cooling water agains the cold side you will be having more cold fluid flowing thru that pipe, meaning that you can transfer more heat to that side of the heat transfer. So the answer would be A. The rate of heat transfer through the material would increase.