Answer:
(1,-1)
(7,12)
(5,-3)
Step-by-step explanation:
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality
we have
[tex]y-2x \leq -3[/tex]
Verify each case
case 1) we have
(1,-1)
substitute the value of x and the value of y in the inequality and then compare the results
[tex]-1-2(1) \leq -3[/tex]
[tex]-3 \leq -3[/tex] ----> is true
therefore
The ordered pair is a solution of the inequality
case 2) we have
(7,12)
substitute the value of x and the value of y in the inequality and then compare the results
[tex]12-2(7) \leq -3[/tex]
[tex]-12 \leq -3[/tex] ----> is true
therefore
The ordered pair is a solution of the inequality
case 3) we have
(-6,-3)
substitute the value of x and the value of y in the inequality and then compare the results
[tex]-3-2(-6) \leq -3[/tex]
[tex]9 \leq -3[/tex] ----> is not true
therefore
The ordered pair is not a solution of the inequality
case 4) we have
(0,-2)
substitute the value of x and the value of y in the inequality and then compare the results
[tex]-2-2(0) \leq -3[/tex]
[tex]-2 \leq -3[/tex] ----> is not true
therefore
The ordered pair is not a solution of the inequality
case 5) we have
(5,-3)
substitute the value of x and the value of y in the inequality and then compare the results
[tex]-3-2(5) \leq -3[/tex]
[tex]-13 \leq -3[/tex] ----> is true
therefore
The ordered pair is a solution of the inequality
