Explanation:
Given:
x₀ = 0 m
v₀ = 0 m/s
v = 26.8 m/s
t = 4.9 s
Find: x
x = x₀ + ½ (v + v₀)t
x = 0 + ½ (26.8 + 0) (4.9)
x ≈ 65.7
The car travels 65.7 meters (round as needed).
Answer: The distance traveled by Ford Mustang GT is 65.7 m
Explanation:
To calculate the acceleration of the car, we use first equation of motion:
[tex]v=u+at[/tex]
where,
v = final velocity of the car = 26.8 m/s
u = initial velocity of the car = 0 m/s
a = acceleration of the car = ?
t = time taken = 4.9 sec
Putting values in above equation, we get:
[tex]26.8=0+(a\times 4.9)\\\\a=\frac{26.8-0}{4.9}\\\\a=5.47m/s^2[/tex]
To calculate the distance traveled by car, we use second equation of motion:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where,
s = distance traveled
u = initial velocity of the car = 0 m/s
a = acceleration of the car = [tex]5.47m/s^2[/tex]
t = time taken = 4.9 sec
Putting values in above equation, we get:
[tex]s=(0\times 4.9)+\frac{1}{2}\times 5.47\times (4.9)^2\\\\s=65.7m[/tex]
Hence, the distance traveled by Ford Mustang GT is 65.7 m
