Answer:
The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.
The HRT is 20.6 days.
Explanation:
First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:
[tex]M=\rho*V=37.5\frac{lb}{ft^3}*1m^3*(\frac{3.281ft}{1m}) ^3=1324.5lb=600.7 kg[/tex]
If the VS are 6% in weight,
[tex]M_{vs}=0.06*M=0.06*600.7\,kg/m^3=36,0kgVS/m3[/tex]
The volume per day needed to feed 2 kg of VS/day is:
[tex]V=\frac{2kg}{36kg/m^3}= 0.055m3/day=5.5litres/day[/tex]
The HRT depends on the volume of the tank and the flow. Its equation is
[tex]HRT=\frac{V}{Q}=\frac{300gal}{0.055 m^3/day}*\frac{1m^3}{264.172gal}\\ \\HRT=20.6\,days[/tex]
