Respuesta :
Answer :
(a) The 60 feet of water is equal to 179344.2 Pa.
(b) The 220 psi is equal to [tex]31680lbf/ft^2[/tex]
(c) The 120 torr is equal to 15998.6 Pa.
(d) The 1.0 atm to inches of glycerin is equal to 323.07 inches.
(e) The 1050 mm Hg is equal to [tex]376.95lbf/ft^2[/tex]
Explanation :
(a) The conversion used from feet to pascal is:
[tex]1\text{ feet}=2989.07Pa[/tex]
As we are given that 60 feet of water. Now we have to convert into Pa.
As, [tex]1\text{ feet}=2989.07Pa[/tex]
So, [tex]60\text{ feet}=\frac{60\text{ feet}}{1\text{ feet}}\times 2989.07Pa=179344.2Pa[/tex]
The 60 feet of water is equal to 179344.2 Pa.
(b) The conversion used from [tex]psi[/tex] to [tex]lbf/ft^2[/tex] is:
[tex]1\text{ psi}=144lbf/ft^2[/tex]
As we are given that 220 psi. Now we have to convert into [tex]lbf/ft^2[/tex].
As, [tex]1\text{ psi}=144lbf/ft^2[/tex]
So, [tex]220\text{ psi}=\frac{220\text{ psi}}{1\text{ psi}}\times 144lbf/ft^2=31680lbf/ft^2[/tex]
The 220 psi is equal to [tex]31680lbf/ft^2[/tex]
(c) The conversion used from torr to pascal is:
[tex]1\text{ torr}=133.322Pa[/tex]
As we are given that 120 torr. Now we have to convert into Pa.
As, [tex]1\text{ torr}=133.322Pa[/tex]
So, [tex]120\text{ torr}=\frac{120\text{ torr}}{1\text{ torr}}\times 133.322Pa=15998.6Pa[/tex]
The 120 torr is equal to 15998.6 Pa.
(d) 1.0 atm to inches of glycerin
Formula used : [tex]P=\rho gh[/tex]
where,
P = pressure of glycerin = 1.0 atm = 101325 Pa
g = acceleration due to gravity = [tex]9.8m/s^2[/tex]
[tex]\rho[/tex] = density of glycerin = [tex]1260kg/m^3[/tex]
Now put all the given values in above formula, we get:
[tex]101325Pa=(1260kg/m^3)\times (9.8m/s^2)\times h[/tex]
[tex]h=8.206\frac{Pa.m^2s^2}{kg}=8.206m=323.07\text{ inches}[/tex]
Conversion used :
[tex]1Pa=\frac{kg}{ms^2}\\\\1m=39.37inches[/tex]
The 1.0 atm to inches of glycerin is equal to 323.07 inches.
(e) The conversion used from [tex]psi[/tex] to [tex]lbf/ft^2[/tex] is:
[tex]1\text{ mmHg}=0.359lbf/ft^2[/tex]
As we are given that 1050 mmHg. Now we have to convert into [tex]lbf/ft^2[/tex].
As, [tex]1\text{ mmHg}=0.359lbf/ft^2[/tex]
So, [tex]1050\text{ mmHg}=\frac{1050\text{ mmHg}}{1\text{ mmHg}}\times 0.359lbf/ft^2=376.95lbf/ft^2[/tex]
The 1050 mm Hg is equal to [tex]376.95lbf/ft^2[/tex]
