contestada

Consider the chemical equations shown here. C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) What is the overall equation for the reaction that produces CCl4 and HCl from CH4 and Cl2?

Respuesta :

joseaaronlara

Answer:

The answer to your question is below

Explanation:

(I)                               C(s) + 2H2(g) → CH4(g)

(II)                             C(s) + 2Cl2(g) → CCl4(g)

(III)                             H2(g) + Cl2(g) → 2HCl(g)

Process

Change (I)          CH4(g)        ⇒    C(s) + 2H2(g)

Add (I) and (II) C(s) + 2Cl2(g) ⇒ CCl4(g)

Result             CH4(g)  + C(s) + 2Cl2(g) ⇒  CCl4(g) + C(s) + 2H2(g)

Simplify           CH4(g)  2Cl2(g) ⇒  CCl4(g) + 2H2(g)     (IV)

Multiply (III) by 2     2( H2(g) + Cl2(g) → 2HCl(g))

                                  2 H2(g) + 2Cl2(g) → 4HCl(g)         (V)

Add (IV) and (V)

                           CH4(g) + 2Cl2(g) ⇒  CCl4(g) + 2H2(g)

                          2 H2(g) + 2Cl2(g) ⇒  4HCl(g)  

   CH4(g) + 2Cl2(g) +  2 H2(g) + 2Cl2(g) ⇒  CCl4(g) + 2H2(g) +  4HCl(g)  

Simplify

           CH4(g) + 4Cl2(g)  ⇒  CCl4(g) + 4HCl(g)

                       

  1.   C(s) + 2H2(g) → CH4(g)
  2. C(s) + 2Cl2(g) → CCl4(g)
  3. H2(g) + Cl2(g) → 2HCl(g)

       When the Process will be:

  • Then Change (I)    CH4(g)   ⇒    C(s) + 2H2(g)
  • After that Add (I) and (II) C(s) + 2Cl2(g) ⇒ CCl4(g)
  • Then the Result is CH4(g)  + C(s) + 2Cl2(g) ⇒  CCl4(g) + C(s) + 2H2(g)
  • Now when we Simplify that is   CH4(g)  2Cl2(g) ⇒  CCl4(g) + 2H2(g)        (IV)
  • Then Multiply (III) by 2     2( H2(g) + Cl2(g) → 2HCl(g))  
  •  Now 2 H2(g) + 2Cl2(g) → 4HCl(g)        (V)

               After that Add (IV) and (V)  

  • Then CH4(g) + 2Cl2(g) ⇒  CCl4(g) + 2H2(g)
  • Then 2 H2(g) + 2Cl2(g) ⇒  4HCl(g)  
  • When CH4(g) + 2Cl2(g) +  2 H2(g) + 2Cl2(g) ⇒  CCl4(g) + 2H2(g) +  4HCl(g)    

                      Now Simplify this  

  • Now CH4(g) + 4Cl2(g)  ⇒  CCl4(g) + 4HCl(g)

Learn more about:

https://brainly.com/question/17036533

                     

Otras preguntas