Answer:
Force of attraction = 35.96 [tex]\times 10^{27}[/tex]N
Explanation:
Given: charge on anion = -2
Charge on cation = +2
Distance = 1 nm = [tex]10^{-9}[/tex] m
To calculate: Force of attraction.
Solution: The force of attraction is calculated by using equation,
[tex]F = \dfrac{k \times q_1 q_2}{ \r^2}[/tex] ---(1)
where, q represents the charge and the subscripts 1 and 2 represents cation and anion.
k = [tex]8.99 \times 10^9 \ Nm^{2}C^{-2}[/tex]
F = force of attraction
r = distance between ions.
Substituting all the values in the equation (1) the equation becomes
[tex]F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }[/tex]
Force of attraction = 35.96 [tex]\times 10^{27}[/tex]N
