Answer:
There are 550.5 moles of methanol in 110.0 kilograms of the mixture.
Explanation:
A solution 15% weight of methanol means there is 15g of methanol per 100g of the mixture or 0.1kg of the mixture. Also, the molar mass of methanol (CH3OH) is:
[tex]m_{C} + 4xm_{H} + m_{O} = 12.0g/mol + 4x1.0g/mol + 16.0g/mol = 32.0g/mol[/tex]
Thus, dividing 15g by molar mass
[tex]15.0g / 32.0\frac{g}{mol} = 0.5moles[/tex] we find there is 0.5 moles of methanol per 0.1Kg of the mixture. Calculating the number of mols of methanol in 110.0 kilograms of the mixture:
[tex]\frac{110.1Kgx0.5moles}{0.1Kg} = 550.5 moles[/tex]
Therefore, there is 550.5 moles of methanol in 110.0 kilograms of the mixture.
