Answer:
1) The density of air at 40 degrees Celsius and 3 atm pressure is 3.4 g/L.
2) Molecular mass of linanyl acetate is 196 g/mol.
Explanation:
1) Average molecular weight of an air ,M= 28.97 g/mol
[tex]PV=nRT[/tex]
or [tex] PM=dRT[/tex]
P = Pressure of the gas
T = Temperature of the gas
d = Density of the gas
M = molar mass of the gas
R = universal gas constant
P = 3 atm, T = 40°C = 313.15 K, M = 28.97 g/mol
[tex]d=\frac{PM}{RT}=\frac{3 atm \times 28.97 g/mol}{0.0821 atm L/ mol K\times 313.15 K}[/tex]
d = 3.4 g/mL
The density of air at 40 degrees Celsius and 3 atm pressure is 3.4 g/L.
2) Molecular formula of Linanyl acetate = [tex]C_{12}H_{20}O_2[/tex]
Atomic mass sof carbon = 12.01 g/mol
Atomic mass of hydrogen = 1.01 g/mol
Atomic mass of oxygen = 16.00 g/mol
Molecular mass of Linanyl acetate :
[tex]12\times 12.01 g/mol+20\times 1.01 g/mol+2\times 16.00 g/mol =196.32 g/mol \approx 196 g/mol[/tex]
